If 2 cos 3a 1 then the value of a is
Web9 jan. 2024 · Tour Start here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site Web22 mrt. 2024 · If sin A + sin 2 A = 1, then the value of the expression (cos 2 A + cos 4 A) is (A) 1 (B) 1/2 (C) 2 (D) 3 This video is only available for Teachoo black users Subscribe Now Get live Maths 1-on-1 Classs - Class 6 to 12. Book 30 minute class for ₹ 499 ₹ 299. Transcript. Question 12 ...
If 2 cos 3a 1 then the value of a is
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WebIf cosA+cos 2A=1, then the value of sin 2A+sin 4A is: A −1 B 0 C 1 D 2 Medium Solution Verified by Toppr Correct option is C) it is Given that cosA+cos 2A=1⇒cosA=1−cos 2A⇒cosA=sin 2A.............(1) Now, sin 2A+sin 4A=sin 2A+(sin 2A) 2=sin 2A+cos 2A=1 (from (1)) Therefore, Answer is 1 Solve any question of Introduction to Trigonometry with:- Web19 apr. 2016 · ∴ The value of tan3A + cot3A is – (2) Alternate Method Put A = 45° tan45° + cot45° = 2 tan135° + cot135° = – (1) + – (1) ⇒ – (2) ∴ The value of tan3A + cot3A is – (2) Download Solution PDF Latest RRB NTPC Updates Last updated on Mar 31, 2024 RRB NTPC Result, Cut Off for Pay Level 5 declared for RRB Chandigarh.
WebSolution Verified by Toppr Correct option is C) Given : acos 3θ+3acosθsin 2θ=m..... (1) asin 3θ+3acos 2θsinθ=n..... (2) Adding equation (1) and (2) we get, ∴m+n=a(cos 3θ+sin 3θ)+3acosθsinθ(cosθ+sinθ)=a(cosθ+sinθ) 3 Similarly, we get m−n=a(cosθ−sinθ) 3 =(m+n) 32+(m−n) 32 =a 2/3[((cosθ+sinθ) 3) 2/3+((cosθ−sinθ) 3) 2/3] WebCalculate the value of A, if cos 3A. (2 sin 2A - 1) = 0 . CISCE ICSE Class 9. Question Papers 10. Textbook Solutions 19278. Important Solutions 16. Question Bank Solutions 14679. Concept Notes & Videos 193 Syllabus ... cos 3A ( 2 sin 2A – 1 ) = 0 cos 3A = 0 and 2 sin 2A – 1 = 0
WebIf sinA+sin 2A+sin 3A=1, then find the value of cos 6A−4cos 4A+8cos 2A is: A 1 B 2 C 3 D 4 Medium Solution Verified by Toppr Correct option is D) sinA+sin 2A+sin 3A=1 ⇒sinA(1+sin 2A)=1−sin 2A ⇒sinA(2−cos 2A)=cos 2A ⇒sin 2A(4−4cos 2A+cos 4A)=cos 4A ⇒(1−cos 2A)(4−4cos 2A+cos 4A)=cos 4A ⇒4−8cos 2A+5cos 4A−cos 6A=cos 4A ∴cos … Webcos 3A ( 2 sin 2A – 1 ) = 0. cos 3A = 0 and 2 sin 2A – 1 = 0. cos 3A = cos90° and 2 sin 2A = 1 2. 3A = 90° and sin 2A = sin 30°. A = 30° 2A = 30° ⇒ A = 15°. Concept: …
Web19 apr. 2016 · The general solution of the equation sin2θ sec θ + √3 tan θ = 0 is: Q9. The values of x satisfying 2 sin 2 x − 2 cos 2 x = 1 are: Q10. Each side of a square ABCD …
WebFind the value of angle A in degrees ifsin2A=1 Medium Solution Verified by Toppr Correct option is A) sin2A=1 sin2A=sin90 o 2A=90 o A=45 ∘ Solve any question of Introduction to Trigonometry with:- Patterns of problems > Was this answer helpful? 0 0 Similar questions Find the value of angle A in degree, if 2sinA=1 Medium View solution > designer steroids that avoided being caughtWebSolve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more. designers that start with a bWebSince cos2A=sin3A, or cos 2A = cos (90–3A), or 2A = 90–3A, or 5A = 90, or A = 18 deg. 3 Varsha Kanwar 1 y Cos2A=sin3A Sin (90–2A)=sin3A Take sine inverse Then 90–2A=3A 5A=90 A=18 6 Vikas Deep Bsc from Dr. Ram Manohar Lohia Avadh University (Graduated 2024) 1 y Continue Reading 3 Vikram Singh Jodha designers technical skillsWeb21 feb. 2024 · Correct Answer - Option 1 : 11/32 Concept: Formula used: cos 3A = 4 cos 3 A – 3 cosA cos 2A = 2 cos 2 A – 1 2sin A sin B = cos (A – B) – cos (A + B) Calculation: sin (5A/2)sin (A/2) Multiply by 2 and divide by 2 in sin (5A/2) sin (A/2) ⇒ 1/2 (2Sin (5A/2)Sin (A/2)) ⇒ 1/2 (Cos (5A/2 – A/2) – Cos (5A/2 + A/2)) ⇒ 1/2 (Cos2A – Cos3A) designer stencils for cake decoratingWeb14 mrt. 2024 · The formula is 4cos3A− 3cosA. Explanation: Use the cosine angle addition formula, then the sine and cosine double angle formulas: = cos3A = cos(A +2A) = … chuckanut manor reservationsWeb13 jul. 2024 · Find the value of cos 3A Solution, cos A = 1/2. Let us first derive the formula for cos 3A. ⇒ cos 3A can be written as- ⇒ cos ( 2A + A). Now, it is of the form cos (A+B) = cos A cos B - sin A sin B. ⇒ cos (2A + A) = cos 2A cos A - sin 2A sin A Now, we know that cos 2A = cos² A - sin² A. = cos²A - (1 - cos² A) ⇒ 2 cos² A - 1 Hence, designers that codeWeb2cos 3A = 1. ⇒ cos 3A = 1 2. ⇒ cos 3A = cos60°. ⇒ 3A = 60°. ⇒ A = 20°. Concept: Trigonometric Equation Problem and Solution. Is there an error in this question or solution? Chapter 27: Trigonometrical Ratios of Standard Angles - Exercise 27.1. Q 4.4 Q 4.3 Q 4.5. designers that makes beaded dresses